If the zeroes of polynomial x^3 -6x^2 + 3x + 10 are α , α + β, α +2β. Find α and β.23.If the zeroes of polynomial
Maths Class 10
Answers
Step-by-step explanation:
The value of \alpha^2+\beta^2=\frac{106}{9}α
2
+β
2
=
9
106
Step-by-step explanation:
Polynomial : p(x) = 3x^2 - 14x +15p(x)=3x
2
−14x+15 whose \alphaα and \betaβ are zeroes .
General equation : ax^2+bx+c=0ax
2
+bx+c=0
Where,
Sum of zeroes = -\frac{b}{a}−
a
b
Product of zeroes = \frac{c}{a}
a
c
Sum of zeroes of given equation : \alpha+\beta=\frac{14}{3}α+β=
3
14
Product of zeroes of given equation : \alpha\beta =\frac{15}{3}=5αβ=
3
15
=5
Formula used,
\begin{gathered}(a+b)^2=a^2+b^2+2ab\\(a+b)^2-2ab=a^2+b^2\end{gathered}
(a+b)
2
=a
2
+b
2
+2ab
(a+b)
2
−2ab=a
2
+b
2
The identity form is
(\alpha+\beta)^2-2 \alpha \beta=\alpha^2+\beta^2(α+β)
2
−2αβ=α
2
+β
2
Substitute the values,
\begin{gathered}(\frac{14}{3})^2-2(5)=\alpha^2+\beta^2\\\\\frac{106}{9}=\alpha^2+\beta^2\end{gathered}
(
3
14
)
2
−2(5)=α
2
+β
2
9
106
=α
2
+β
2
Therefore, the value of \alpha^2+\beta^2=\frac{106}{9}α
2
+β
2
=
9
106
#Learn more:
If alpha and beta are the zeroes of the polynomial p(x) = 3x2 - 14x +15 ,find the value of alpha square + beta square