Question

if the zeroes of polynomial x square -8x +k=0.are the HCF of (6,12), then the value of k _____​

Answer 1

Step-by-step explanation:

Given −3 is the zero of the polynomial (k−1)x

2

+kx+1

So −3 must satisfy the equation (k−1)x

2

+kx+1=0

⟹(k−1)(−3)

2

+k(−3)+1=0

⟹9(k−1)−3k+1=0

⟹9k−9−3k+1=0

⟹6k=8

⟹k=

3

4