if the zeroes of polynomial x3-3x2+x+1 are α-b,α,α+b find α and b
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Alpha equal a-b
beta = a
gamma = a+b
we know that alpha + beta + Gama equal -b/a
put value
a-b+a+a+b= -(-3/1)
we get
3a = 3
a= 1
similarly put Alpha into beta into GamMa = -d/a
putting value u will get b
beta = a
gamma = a+b
we know that alpha + beta + Gama equal -b/a
put value
a-b+a+a+b= -(-3/1)
we get
3a = 3
a= 1
similarly put Alpha into beta into GamMa = -d/a
putting value u will get b
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