Question

if the zeroes of polynomial x³ - 3x²+x+1 are in AP then find the value of a and b​

Answer 1

Step-by-step explanation:

sum of zeroes=a-d+a+a+d=3a

3a=-b/a=3

a=1

Product=(a-d)a(a+d)

=a^4-a^2×d^2

=1-d^2

=-d/a

=-1

d^2=2

d=√2

Common difference is √2