Question

if the zeroes of polynomials 2x2 - 3x + alpha and ax2 - 6x + u are same , then alpha a/u =

Answer 1

Let,

$f(x) = 2 {x}^{2} - 3x + \alpha \\ g(x) = a {x}^{2} - 6x + u$

Since zeroes of f(x) = zeroes of g(x)

Let,

Zeroes be ->

P and Q

therefore, P.Q = alpha/2 = u/a

Hence, a/u = 2/alpha.