if the zeroes of quadratic polynomial x²+(a+1)+b are 2 and -3 then value of a and b
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Zeroes = 2 and -3 .
so , 2 and 3 will makes the given quadratic equation zero.
p(x)=0
putting the zero 2 to the given quadratic equation
=>2^2+(a+1)x+b=0
=>4+ax+x+b=0
=>b=-4-ax-x........(i)
p(-3) =0
=>-3^2+(a+1)x+b
=>9+ax+x+b=0
now putting the value of b from equation (i)
=>9+ax+x+-4-ax-x=0
=>5
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