Question

If the zeroes of the given quadratic polynomial are 2 and -3 ,then find value of a and b . x2+(a+1)x+b​

Answer 1

Step-by-step explanation:

Correct option is

D

a=0,b=−6

x

2

+(a+1)x+b is the quadratic polynomial.

2 and −3 are the zeros of the quadratic polynomial.

Thus, 2+(−3)=

1

−(a+1)

=>

1

(a+1)

=1

=>a+1=1

=>a=0

Also, 2×(−3)=b

=>b=−6