If the zeroes of the polynomial 3x2 –11x+k are reciprocal to each
other, then the value of k is
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Answers
Answered by
2
EXPLANATION.
- GIVEN
zeroes of the polynomial = 3x² - 11x + k
are reciprocal to each other.
Find value of k is.
according to the question,
products of zeroes of quadratic polynomial
=> ab = c/a
quadratic polynomial are reciprocal to each
other => a X 1/a = 1
=> 1 = c/a
=> 1 = k/3
=> k = 3
Therefore,
Value of k = 3
Formula of quadratic polynomial.
=> sum of zeroes of quadratic polynomial.
=> a + b = -b/a
=> products of zeroes of quadratic polynomial.
=> ab = c/a
Equation of quadratic polynomial.
=> x² - ( a + b )x + ab
Answered by
1
Answer:
Let one root of the given that other zero is Reciprocal the one zero.
So,
Other zero=1/Alpa.
Given polynomial is 5x
2
+13x+k=0.
Here,
A=coefficient of x
2
B=coefficient of x
And,C=constant term.
Product of zeroes =C/A
Alpha ×1/Alpha =K/5
1=K/5
K=5
Then,
We get k=5.
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