If the zeroes of the polynomial
ଶ + + are double in value to the zeroes of 2
ଶ − 5 − 3, find the value of
and .
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Answer:
2x2−5x−3=0
2x2−6x+x−3=0
(x−3)(2x+1)=0
x=3,−21
Now,
Zeroes of the polynomial x2−px+q are double in values to the zeroes of polynomial 2x2−5x−3.
Therefore,
Zeroes of polynomial x2−px+q will be- 6,−1
Therefore,
Sum of roots =a−b
6+(−1)=−(−p)
⇒p=5
Product of root =ac
6×−1=q
⇒q=−6
Hence the values of p and q are 5 and −6 respectively.
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