If the zeroes of the polynomial are x³-3x²+x+1
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➡Given here.
♠ X³ -3x² +x +1.
= x³ - x² -2x² +2x -x +1.
= x²(x-1)-2x(x-1)-1(x-1).
= (x-1)(x²-2x-1).
➡Now , factor of (x²-2x-1)
♠Use Dharacharya Formula .
X = [- B ± √ (B² -4AC )] /2A.
=> X = [ - (-2) ± √ {(-2)²-4*1*(-1)}]/2*1
=> X = [ 2 ± √ { 4 +4}]/2
=> x = [ 2±√8]/2.
=> X = 2(1±√2)/2.
=> X = (1±√2).
➡So, Factor of this equations .
♠ x = 1, (1±√2).
#BAL #Answerquality
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