Question

If the zeroes of the polynomial f(x) =x^3-3^2+x+1 are (a-b), a and (a+b), find the a and b​

Answer 1

Answer:

cbvdghnhfffhnvdddghjjc

Answer 2

Answer:

a−b,a,a+b are zeroes of x ³−3x² +x+1

⇒a−b+a+a+b= sum of zeroes = 3

⇒3a=3

⇒a=1

(a−b)(a)(a+b)= product of zeroes =−1

⇒(1−b)(1+b)=−1

⇒1−b² =−1

⇒b²=2

⇒b=±√2