if the zeroes of the polynomial

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Sum of roots = a - b + a + a + b = 3.
=> 3a = 3.
=> a = 1.
Product of roots = (a - b)a(a + b) = -1.
=> (a² - b²)a = -1.
=> a³ - ab² = -1.
=> (1)³ - (1)b² = -1. (a = 1).
=> 1 - 1b² = -1.
=> -1b² = -1 - 1.
=> -1b² = -2.
=> b² = 2.
=> b = ±√2.
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