Question

If the zeroes of the polynomial x^2-3x^2+x+1 are a-b,a,a+b find the values of and b

Answer 1

Answer:

Hello

Step-by-step explanation:

Ans is since (a-b) and (a+b) or a are the zeroes of polynomial of x3-3x2+x+1.

Therefore,sum of zeroes =(a-b), a+b, a = - (-3)/1.

So, 3a=3 and.

A= 1..

:-sum of the product of zeroes taken two at a time. =a(a-b) +a(a+b) +(a-b) (a-b) =1/1=1

A*2-ab+a*2+ab+a*2-b*2=1

3a*2-b*2=1

3(1)*2-b*2=1

3-b*2=1

B*2=2 or b=+, - root2.

Thnks...