Question

If the zeroes of the polynomial x^2 -5x + k are the reciprocal of each other,then 2find the value of k

Answer 1

Answer:

the zeroes are reciprocals of each other.

let alpha and beta be the zeroes

alpha = 1/beta

x² - 5x + k = 0----(1)

x² - (alpha + beta)x + alpha x beta = 0

x² - (1/beta + beta)x + 1/beta x beta = 0

x² - (1+beta²/beta)x + 1 = 0 -----(2) [beta and beta got cancelled]

now in eq (1) &(2) we can say that k = 1

mark brainliest

Answer 2

Answer:

$\gamma \gamma \alpha \gamma \beta \alpha \beta \alpha \gamma \gamma \gamma \alpha \gamma \alpha \sin( \cot( \cos( \sec( \csc( \csc( \sin( \sin( \sin(e \cos( \cos( \cot( \sin( \sec( \sin( \sin( \sec( \sin( \sin( \sin( \sec( \sin( \sin( \sin( \cos( \infty \tan(\pi\pi \alpha \alpha \alpha \alpha ln(\pi log( \infty log_{ \binom{\%\% \binom{ \\ \binom{ \\ \binom{ \\ \\ \binom{ \\ \\ \binom{ \binom{ \\ \binom{?}{?} }{?} }{?} }{?} }{?} }{?} }{?} }{?} }(?) ) ) ) ) ) ) ) ) ) ) ) ) ) ) ) ) ) ) ) ) ) ) ) ) ) ) ) )$

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