If the zeroes of the polynomial x 3 −3x 2 +x+1 are a−b,a,a+b find a 2and b 3
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This question if From NCERT Ex 2.4
- Firstly add all the Zeroes of Polynomial a + a + b + a -b
- We have a Formula alpha + Bita + Gama = -b/a (Here alpha Bita Gama are the Zeroes of Polynomial and b is Constant in Polynomial b = -3 According to Polynomial and a is also 1 as it is Coefficient of X^3
- We got 3a = 3 (After Calculation)
- Then we got Value of a = 1
- Now its Time to Find the value of B
- We have to use Another Formula for Value of B The Formula is Alpha *Bita*Gama = d/a
- Here d is The Constant in Polynomial D = 1
- After Doing Calculation on LHS We got a^3 - b^2a (Cube of A - square of B multiplied by A
- Now put the Value of A in the Equation Which we have Find out from Above
- Then Equation will be 1 - b^2
- Take 1 to the RHS
- -b^2 = -2
- b^2 = 2
- b = √2
- As we Know that if any no is in root it may be in positive or Negative
- so b = +-√2
Hope This Helped You
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