If the zeroes of the polynomial x^3 - 3x^2 + x + 1 are a - b, a and a + b, then find a and b.
Class X [ NCERT ]
Polynomial chapter
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Sum of zeroes = ( - coefficient of x^2)/coefficient of x^3
a- b + a + a + b= ( -(-3))/1
3a = 3
a= 1
And product of zeroes = - constant term/coefficient of x^3
( a-b)( a)( a+b)= -1
put a= 1
( 1-b)( 1+b)= -1
1 - b^2 = -1
b^2 = 2
b= +-√2
So a = 1
and b= +-√2
✌✌✌✌Dr.Dhruv✌✌✌✌✌
a- b + a + a + b= ( -(-3))/1
3a = 3
a= 1
And product of zeroes = - constant term/coefficient of x^3
( a-b)( a)( a+b)= -1
put a= 1
( 1-b)( 1+b)= -1
1 - b^2 = -1
b^2 = 2
b= +-√2
So a = 1
and b= +-√2
✌✌✌✌Dr.Dhruv✌✌✌✌✌
Anonymous:
nice ^_^
Answered by
4
#RAM RAM ji ❤☺
ĀNSWĒR ⏬⏬
given equation ▶
a▶1
B▶+-√2
THANKS ✌
#NAVI ❤ HARYANVI ♠
ĀNSWĒR ⏬⏬
given equation ▶
a▶1
B▶+-√2
THANKS ✌
#NAVI ❤ HARYANVI ♠
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