Question

if the zeroes of the polynomial x^3-3x^2+x+1 are a-b,a+b find a and b

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Answer 1

Answer:

hope it's help you....

Answer 2

Answer:

GIVEN-

a-b,a,a+b are the zeroes of x³-3x²+x+1

Solution-

a-b+a+a+b=sum of zeroes

=3a=3

Therefore a=1

(a-b)(a)(a+b)=product of zeroes=-1

(1-b)(1+b)=-1

1-b²=2

b= ± 2

here is your answer mate....

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