If the zeroes of the polynomial x^3-3x^2+x+1are (a-b),(a+b),(a)find a and b.
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sum of roots
a-b+a+b+a=3
3a=3
a=1
product of roots
since a =1
(1-b)(1+b)1=-1
1-b^2=-1
b^2=2
b=√2
clearly solved solution is attached.
a-b+a+b+a=3
3a=3
a=1
product of roots
since a =1
(1-b)(1+b)1=-1
1-b^2=-1
b^2=2
b=√2
clearly solved solution is attached.
Attachments:
goutham34:
thanks
Answered by
0
Here is ur another solution
Attachments:
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