If the zeroes of the polynomial x2 — ax + b are 3 and 4, then 'a' and 'b' are respectively equal to
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a=7
b=12
Solution
When x =3,
x2-ax+b=0
3*3 -a*3+b=0
9-3a+b=0(eqn. 1)
when x =4,
4*4-a*4+b=0
16-4a+b =0(eqn 2)
on subtracting eqn. 1 from 2
16-4a+b=0
9 -3a+b=0
- +. -
____________
7 -a. = 0
_____________
a= 7
From eqn 1
9 - 3a +b = 0
9-3*7+b =0
9-21+b=0
-12+b=0
b=12
Hope it helps
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