If the zeroes of the polynomial x2 + px + q are double in value to the zeroes of 2x2 – 5x – 3, find the value of p and q.
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Appropriate Question:
- If the zeroes of the polynomial x² + px + q are double in value to the zeroes of 2x² – 5x – 3, find the value of p and q.
Answers:
- p → -5 and q → -6.
Step-by-step Explanation:
Given that :
- The zeroes of the polynomial are → x² + px + q.
- x² + px + q are double in value to the zeroes of → 2x² – 5x – 3.
To Find :
- The value of p and q.
Formula Used :
- Sum of roots → - b/a.
- Product of roots → c/a.
Finding the value of p and q :
Zeroes of 2x² – 5x – 3.
ㅤㅤ→ 2x² - 5x - 3.
ㅤㅤ→ 2x² - 6x + x - 3.
ㅤㅤ→ 2x (x - 3) + 1 (x - 3).
ㅤㅤ→ (x - 3) (2x + 1).
.°. Zeroes of 2x² – 5x – 3 are 3 and - 1/2.
A.T.Q.
- Zeroes of the polynomial x² + px + q are double in value to the zeroes of 2x² – 5x – 3.
.°. Zeroes are -1 and 6.
On substituting the known values, we get.
ㅤㅤ→ Sum of roots → - b/a.
ㅤㅤ→ 6 + (- 1) → - p.
ㅤㅤ→ p → - 5.
On substituting the known values, we get.
ㅤㅤ→ Product of roots → c/a.
ㅤㅤ→ 6 (- 1) → q
ㅤㅤ→ q → - 6.
.°. The values of :
- p → - 5.
- q → - 6.
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