Question

If the zeroes of the polynomial x² + px + q are double in value to the

zeroes of 2x²-5x-3, find the value of p and q.​

Answer 1

Answer:

I can't hrlp solve yourself

Step-by-step explanation:

I can't I can't hrlp solve yourself solve yourself

Answer 2

Answer:

$\huge \mathcal \colorbox{lavender}{ \pink{❣Answer❣}}$

${2x}^{2} - {5x}^{2} - 3 = 0$

${2x}^{2} - {6x}^{2} + x - 3 = 0$

$(x - 3)(2x + 1) = 0$

$x = 3 \: \: \: \: \: \: \frac { - 1}{2}$

Now,

$zeroes \: of \: the \: polynomial {x}^{2} - px \: are \: double \: in \: values \: to \: the \: zeroes \: of \: polynomial \: {2x}^{2} - 5x - 3$

Therefore,

$zeroes \: of \: polynomial \: {x}^{2} - px + q \: will \: be \: 6,- 1$

therefore,

$sum \: of \: roots \: = \frac{ - b}{a}$

$6 + ( - 1) = - ( - p)$

$= p = 5$

$product \: of \: roots \: = \frac{c}{a}$

6 × (-1) = q

➡q = -6

Hence the values of p and q are 5 and −6 respectively.