if the zeroes of the polynomial x³-3x²+x+1 are a-b,a,a+b,find a and b
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the factors of polynomial are 1,1-√2,1+√2
so a=1 b=√2
so a=1 b=√2
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x^3-3x^2+x+1=(x-1)(x-1+2^1/2)(x-1-2^1/2)
zeroes are 1,1-2^1/2,1+2^1/2
=>a=1,b=2^1/2.
zeroes are 1,1-2^1/2,1+2^1/2
=>a=1,b=2^1/2.
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