if the zeroes of the polynomial x3+3x2+x+1 are a-b, a, a+b find a and b
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Answered by
5
sum of the root is = -b/a
3a = -3
a = -1
product of the root is = -d/a
a³ - ab² = -1
-27 + 3b² = -1
b² = 26/3
b = √(26/3) or -√(26/3)
3a = -3
a = -1
product of the root is = -d/a
a³ - ab² = -1
-27 + 3b² = -1
b² = 26/3
b = √(26/3) or -√(26/3)
Answered by
2
sum of the root is = -b/a
3a = -3
a = -1
product of the root is = -d/a
a³ - ab² = -1
-27 + 3b² = -1
b² = 26/3
b = √(26/3) or -√(26/3)
3a = -3
a = -1
product of the root is = -d/a
a³ - ab² = -1
-27 + 3b² = -1
b² = 26/3
b = √(26/3) or -√(26/3)
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