if the zeroes of the polynomials x^3 -3x^2+x+1 are a-b,a,a+b.then find the value of a and b
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In a cubic equation ax³ + bx² + cx + d,
Sum of roots = -b/a
Product of roots = -d/a
Sum of roots = (a+b + a + a-b) = 3a = -(-2)
∴ a = 2/3
(a - b)(a)(a + b) = -1
(2/3)(4/9 - b²) = -1 ------ { using (a+b)(a-b) = a² - b² }
b² = 4/9 + 3/2 = 35/18
∴ b = √(35/18)
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