Question

If the zeroes of the quadratic 2 po
polynomial x2 + (a + 1) x + b are
2 and -3, then​

Answer 1

Step-by-step explanation:

x=2

4+(a+1)2+b=0

4+2a+2+b=0

2a+b=-6

if x=-3

9+(a+1)-3+b=0

9-3a-3+b=0

3a-b=6

now we have two equations

2a+b=-6

b=-6-2a

by substituting b in second equation

3a-b=6

3a-(-6-2a)=6

3a+2a+6=6

5a=0

a=0

b=-6