Question

If the zeroes of the quadratic equation x²+(a+1)+bx are 2 and -3 , then find the value of a and b

Answer 1

Answer:a=3 b=-6

Step-by-step explanation:

Compare the equation with ax^2+bc+c=0

Therefore a=1 b= (a+1) c=b

We know: alpha =2 and beta =-3

Alpha= -b/2a

= a+1/2×1

2=a+1/2

2×2=a+1

4=a+1

a=4-1

a=3

Beta=c/a

-3=b/2×1

-3=b/2

-3×2= b

-6=b

b=-6