Math, asked by jagpal96433819, 1 year ago

If the zeroes of the quadratic equation x²+(a+1)+bx are 2 and -3 , then find the value of a and b

Answers

Answered by Anonymous
2

let f(x)=x^2+(a+1)+bx

if 2 and -3 are zeros of this equation then they will satisfy this equation

f(2)=4+(a+1)+2b=0 marks 1st equation

f(-3)=9+(a+1)-3b=0 mark as 2nd equation

subtract 1 from 2

9+(a+1)-3b =0

4+(a+1)+2b=0

- - -

5-5b=0

b=1

put value of b in 1st

4+a+1+2=0

a=-7

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