If the zeroes of the quadratic equation x²+(a+1)+bx are 2 and -3 , then find the value of a and b
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let f(x)=x^2+(a+1)+bx
if 2 and -3 are zeros of this equation then they will satisfy this equation
f(2)=4+(a+1)+2b=0 marks 1st equation
f(-3)=9+(a+1)-3b=0 mark as 2nd equation
subtract 1 from 2
9+(a+1)-3b =0
4+(a+1)+2b=0
- - -
5-5b=0
b=1
put value of b in 1st
4+a+1+2=0
a=-7
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