Question

If the zeroes of the quadratic polynomial 2x² – 7x + 49 are a and ß , then what is the value of 1/a+1/b​

Answer 1

Answer:

Given that,

α,β are the zeroes of the polynomial p(x)=2x

2

−7x+3

Sum of zeroes (α+β)=

a

−b

=

2

−(−7)

=

2

7

Product of zeroes αβ=

a

c

=

2

3

∴α

2

+β

2

=(α+β)

2

−2αβ

=(

2

7

)

2

−2(

2

3

)

=

4

49

−

4

12

=

4

37