Question

If the zeroes of the quadratic polynomial are 2 and –3, then
x^2 + ( a+1)x + b
a = –7, b = –1
a = 5, b = –1
a = 2, b = – 6
a = 0, b = – 6​

Answer 1

Answer:

$a = 0$

$b = - 6$