Question

If the zeroes of the quadratic polynomial given below are 2 and -3, x² +(a+1)x+b

Answer 1

Answer:

Step-by-step explanation:

Let f(x)=x²+(a+1)x+b

Such that f(2)=0 and f(-3)=0

F(2)=4+2a+2+b

4a+b+6=0

4a+b=-6_____equation1

F(-3)=9-3a-3+b

9-3a-3+b=0

6-3a+b=0

-3a+b=-6_____equation 2

By solving the equation

a=0 b=-6

F(x)=x²+(0+1)x—6

=X²+x-6

Method 2

Since the roots of the equation are 2 and -3,

F(x)=x²-(sum of roots)x+product

F(x)=x²—(-3+2)x+(-3)(2)

=X²+x—6

Now

Since

a+1=1

a=0

b=-6

Please rate my answer and Mark me as brainiest if this answer help you