Question

if the zeroes of the quadratic polynomial X^2+(a+1)x+b are 2 and -3 then a=? b=?​

Answer 1

Answer:

a =0

b = -6

Step-by-step explanation:

=x^2+(a+1)x+b

= alfa+beta =-(a+1)/1

=2+(-3) =-(a+1)/1

1 =a+2

a = 0

alfa×beta =b/1

(2)(-3) = b

b =-6

hence, a = 0

b = -6