if the zeroes of the quadratic polynomial x^2 + (a + 1)x + b are 2 & -3, then find the value of a and b.
Answers
Answered by
3
ok so
x²+(a+1)x+b
(1) à+ß= -(a+1)
2-3=-a-1 (given)
-1=-a-1
0=-a
0=a
(2)a×ß=b
(2)(-3)=b
-6=b
so a and b are 0and -6 respectively.
I hope it clear your doubts and would be brainiest answer.
x²+(a+1)x+b
(1) à+ß= -(a+1)
2-3=-a-1 (given)
-1=-a-1
0=-a
0=a
(2)a×ß=b
(2)(-3)=b
-6=b
so a and b are 0and -6 respectively.
I hope it clear your doubts and would be brainiest answer.
Answered by
1
Answer:
hi PLz follow me and Marke me brainliest and thanks
Similar questions