Question

If the zeroes of the quadratic polynomial x2 + (a + 1) x + b are 1 and -3, then
A. a=-7 b=-1
B. a=1 b=-3
C. a=2 b=-6
D. a=0 b= -6​

Answer 1

Answer:

option b is correct

Step-by-step explanation:

a+1=-(1-3)

a=1

b=1×-3

b=-3

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Answer 2

Question:

If the zeroes of the quadratic polynomial x2 + (a + 1) x + b are 1 and -3, then

A. a=-7 b=-1

B. a=1 b=-3✔✔

C. a=2 b=-6

D. a=0 b= -6

Answer:

$\large{ \mathrm{if \: \alpha \: and \: \beta \: are \: the \: zeroes}} \\ \\ \large{ \mathrm{ \star{then \: quadratic \: polynomial.... = > }}} \\ \large{ \mathrm{ \boxed{ {x}^{2} - ( \alpha + \beta )x + \alpha \beta }}} \\ \\ \large{ \mathrm{let \: \: \alpha = 1 \: and \: \beta = - 3}} \\ \\ \large{ \mathrm{ \to \: p(x) = {x}^{2} - (1 + ( - 3))x + (1)( - 3)}} \\ \large{ \mathrm{ \to \: p(x) = {x}^{2} + 2x - 3}} \\ \\ \large{ \mathrm{we \: have \: p(x) = {x}^{2} + (a + 1)x + b = 0}} \\ \large{ \star{ \mathrm{ \bold{by \: comparing....}}}} \\ \\ \large{ \mathrm{ \to \: a + 1 = 2}} \\ \large{ \mathrm{\implies{ \boxed{\: a = 1}}}} \\ \\ \large{ \mathrm{\implies{ \boxed{ \: b = - 3}}}}$

$\huge{ \boxed{ \bold{ \red{a = 1 \: and \: b = - 3}}}}$

Option B...