Question

If the zeroes of the quadratic polynomial x² + (a + 1) x + b are 2 and -3, then

Answer 1

Answer:

1st method

sum of zeroes = [-cofficient of x/cofficient of x^2]

2= -b/a

b=-2

a=1

product of zeroes =[constant term / cofficient of x^2]

-3=c/a

c= -3

a=1

we also know tge quadratic form is =ax^2+bx+c

a=1, b= -2, c= -3

x^2-2x-3

2nd method

x^2- (sum of zeroes )x+ product of zeroes

x^2-2x+(-3)

x^2-2x-3

all method we have same answer

hope it's helpful for u

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