Question

If the zeroes of the quadratic polynomial x²+ (a + 1) x + b are 2 and -3, then

Answer 1

Answer:

Step-by-step explanation:

p(x)=x²+ (a + 1) x + b

p(2)=0

2^2 + ( a+1) 2 +b=0

6+2a +b =0

p(3)=0

3^3 + (a + 1) 3 + b=0

30 +3a +b =0

6+2a +b = 30 +3a +b

b-b=30-6+3a-2a

0=24 + a

a=-24

if a=-24

then,

6-48+b=0

b=42

Hope it will help you!!