Question

If the zeroes of the quadratic polynomial x2+ (a+1)x+b are 2 and -3 , then find the
value of a and b.

Answer 1

Answer:

$2 \: and \: \: \: \: - 3 \: \: \: are \: the \: zeros \: of \: the \: equation \: \: {x}^{2} + (a + 1)x + b \: \: \\ \: so \: \\ 2 - 3 = - (a + 1) \\ - 1 = - a - 1 \\ a = 0 \\ \\ \\ 2 \times ( - 3) = b \\ b = - 6$

Answer 2

Answer:

a = 0 and b = -6

refer the pic for step by step explanation