Question

If the zeroes of the quadratic polynomial x2 + (a + 1)x + b are 2 and –3, then find the respective

values of a and b.​

Answer 1

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Answer 2

Given,

p(x)= $x^{2} + (a+1)x +b$

2 and -3 are the zeros of p(x)

To find,

The value of a and b

Solution,

Let,

α= 2 and β = -3

We know that,

Sum of zeros => α + β =$\frac{-b}{a}$

=> 2 × -3 =$\frac{(a+ 1)}{1}$

=> -6 = a+1

=>  a = -6-1

=>  a = -7

Product of zeros => αβ = $\frac{c}{a}$

=> 2 × -3 = $\frac{b}{1}$

=> -6 = b

=> b = -6

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