Question

If the zeroes of the quadratic polynomial x2 + (a + 1) x + b are 2 and -3, then what is the value of a and b

Answer 1

Answer:

According to the problem statement, we are given a quadratic polynomial ${{x}^{2}}+\left( a+1 \right)x+b$ having 2 and -3 as zeroes. Therefore, $\alpha =2\text{ and }\beta =-3$. So, the respective values are a = 0 and b = -6. Therefore, option (d) is correct.

Step-by-step explanation:

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Answer 2

Answer:

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