If the zeroes of the quadratic polynomials x 2 + (a + 1)x + b are 2 and -3, then a=, b=
•a = -7, b = -1
•a = 5, b = -1
•a = 2, b = -6
•a = 0, b = -6
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Last option - a = 0, b = -6
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