Question

if the zeroes of the rational expression[ax+b][3x+2] is -3/2 and 1/2 what is the value of a+b

Answer 1

Answer:

0

Step-by-step explanation:

=(ax+b)(3x+2)

=3ax²+2ax +3bx+2b

=3ax²+x(2a+3b)+2b

A= 3a, B=2a+3b,C=2b

sum of zeroes = -b/a

--3/2+1/2 = -(2a+3b)/3a

-1 ×3a= -2a-3b

-3a = -2a-3b

3a = 2a + 3b

a = 3b ....¡

product of zeroes = c/a

-3/2×1/2= 2b/3a

-3/4 = 2b/3a

-9a = 8b

9a = -8b ....¡¡

multipying eq i by 9

9a- 27b = 0 ....iii

from eq ii and iii

9a- 27b = 0

9a+ 8b = 0

b= 0

a=0

a+b = 0