Question

if the zeroes of x^2-kx+6 are in the ratio 3:2 ,Find x​

Answer 1

It would be find the value of k instead of x.

So this is the answer. And please mark my answer brainliest.

Since the zeroes are in ratio 3:2, we can assume them to be 3a and 2a.

So, p(x)= x² - kx + 6 = x² - (sum of zeroes)x + product of zeroes.

comparing both sides, we get,

6 = product of zeroes = 3a×2a =6a²

6= 6a²

a=±1

k = sum of zeroes = 3a+2a = 5a = ±5

Hence, k = ±5.

Hope you understand the approach.

All the best!