Question

If the zeroes of x ^2- mx + 6 are in the ratio 2:3, find m.​

Answer 1

Given:

The zeroes of p(x) = x² - mx + 6 = 0 are in the ratio 2:3

To find:

The value of m.

Solution:

Let the zeroes be = 2y, 3y

Product of zeroes = c/a

=> 2y × 3y = 6

=> 6y² = 6

=> y = 1

Sum of zeroes = -b/a

=> 2y + 3y = m

=> 5y = m

Put value of y. y = 1

=> 5(1) = m

=> m = 5