Question

if the zeroes of x2+x+k are reciprocals of each other,find the value of k​​. pls help fast

Answer 1

Answer:

hence, the value of k is 1

Step-by-step explanation:

equation x^2 + x + k

comparing with ax^2 + bx + c

we get, a = 1, b = 1 , c = k

roots are reciprocal to each other

let one root p other root 1/p

product of roots = c/a

so, p × 1/p = k/1

so, k = 1

Answer 2

Answer:

let the first zero be ß

then other zero will be , 1/ß

now

given quadratic equation is

x² + x + k

and

product of zeroes = constant term/coefficient of x²

$= > \beta \times \frac{1}{ \beta } = \frac{k}{1} \\ = > 1 = k$

or

k = 1...

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