if the zeros of f(x)= x cube -3 x squqre +x+1 are a-b , a , a+b find a and b and zeros
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Step-by-step explanation:
sum of roots = -(-3)/1 = a-b+a+a+b = 3a
so , a = 1
product of roots = -(1)/1 = a(a²- b²)
= 1(1 - b²)
so , 1-b² = -1
b² = 2
so the values of a,b are 1,±√2 respectively
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