if the zeros of p(x)=2x2-x+k are reciprocal of each other then value of k is
Answers
Answered by
16
Answer:
2
Step-by-step explanation:
First the zero be alpha and
second reciprocal is one upon alpha
so,
product of zeroes=c upon a
alpha×1/alpha=K/2
1=K/2
K=2
hence,the value of K is 2
Answered by
4
it's simple dude
just remember this formula
sum of the roots of quadratic polynomial=constant term/coefficient of x^2
sum=-coefficient of x/ coefficient of x^2
let the first root be x then other will be 1/x
sum,of roots=1/2
x+1/x=1/2
2x^2+2=x
2x^2+2-x=0
x={1+(1-8)^1/2}/2
here,we r seeing that,the discriminant(b^-4ac) is with negative sign
this shows that,no root can be possible,of the polynomial,given,which satisfy the condition of one root reciprocal to another.......
hope it helps
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