if the zeros of polynomial x cube + 9 x square - 3 x + 5 are a-b,a, a+ b then find a and b
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Heya it's Aastha.......
●On comparing equation with standard form.
A =1 , b =9, c = -3 , d = 5 .
◆Sum of zeroes = -b/a
( a -b)+ (a+b)+a. = -9/1
3a = -9
a = -3 .
◆ product of zeroes= -d/a
(a -b )(a+b)a = -5/1
a2-b2 ) a. = -5
-3^2 - b2 ) -3. = -5
-27 - 3b2. = -5
-3b = 22
b. = -22/3.
I hope it help you
●On comparing equation with standard form.
A =1 , b =9, c = -3 , d = 5 .
◆Sum of zeroes = -b/a
( a -b)+ (a+b)+a. = -9/1
3a = -9
a = -3 .
◆ product of zeroes= -d/a
(a -b )(a+b)a = -5/1
a2-b2 ) a. = -5
-3^2 - b2 ) -3. = -5
-27 - 3b2. = -5
-3b = 22
b. = -22/3.
I hope it help you
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