If the zeros of polynomial x cube minus 3 x square + x + 1 hour alpha minus beta alpha and alpha + beta find alpha and beta
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Answered by
18
Given that cubic polynomial,
x³-3x²+x+1
then,
(a-b)+a+(a+b)=-b/a
3a=-(-3)/1
3a=3
a=3/3
a=1
Again,
(a-b)*a*(a+b)=-d/a
a(a²-b²)=-1/1
1(1²-b²=-1
1-b²=-1
-b²=-1-1
-b²=-2
b±2
b=±√2
that
a=1
b=√2
Answered by
3
Answer:
alpha = and beta = √2
Explanation:
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