Question

if the zeros of polynomial X square + bx + c are reciprocal to each other find the value of c​

Answer 1

Answer:

c = 1

Step-by-step explanation:

Let x² + bx + c have roots p and 1/p (∵ roots are reciprocal to each other)

We know that ,

product of roots = constant coefficient / coefficient of x²

∴ p × 1/p = c / 1

∴ c = 1