Question

If the zeros of polynomial x2-5x+6 are the dimensions of rectangle then find its perimeter

Answer 1

Answer:

Given that,

Area of the rectangle = X^2-5x+6

Factorising the polynomial to find it's Dimensions

x^2-5x+6

=> x^2-3x-2x+6

=> x(x-3)-2(x-3)

=> (x-2) (x-3)

x-2=0 x-3=0

x=2 x=3

Therefore,

The Dimensions of the polynomial are 2 and 3

L=3,B=2

Perimeter of the rectangle =2(l+b)

=2(3+2)

=2(5)= 10

Answer 2

Answer:

Required perimeter is 10 unit.

Step-by-step explanation:

Given polynomial is ${x}^{2} - 5x + 6$

Let f(x)$= {x}^{2} - 5x + 6$

When f(x)=0

${x}^{2} - 5x + 6 = 0$

By middle term method,

${x}^{2} - (3 + 2)x + 6 = 0$

${x }^{2} - 3x - 2x + 6 = 0$

$x(x - 3) - 2(x - 3) = 0$

$(x - 3)(x - 2) = 0$

$(x - 3) = 0 \: \: or(x - 2) = 0$

x=3 or 2

According to question 3 and 2 is dimension of rectangle.

Therefore length of rectangle is 3 and breath of rectangle is 2.

We know perimeter of rectangle

$= 2 \times (length + breath)$

$= 2 \times (3 + 2) = 10$unit.