Question

if the zeros of polynomials 2x^2-3x+alpha and ax^2 -6x+Gama are same then alpha a/ Gama​

Answer 1

Answer:

α+β=−1,αβ=2,γ+δ=−3,γδ=4

Now, (α+γ)(α+δ)(β+γ)(β+δ)

=(α

2

+(−3)α+4)(β

2

−3β+4)

=(−α−2−3α+4)(−β−2−3β+4)

=(−4α+2)(−4β+2)

=4(2α−1)(2β−1)

=4(4αβ−2α−2β+1)

=4(8+2+1)=44